-3p^2+800p=0

Solution for -3p^2+800p=0 equation:

-3p^2+800p=0

a = -3; b = 800; c = 0;
Δ = b2-4ac
Δ = 8002-4·(-3)·0
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-800}{2*-3}=\frac{-1600}{-6}
=266+2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+800}{2*-3}=\frac{0}{-6}
=0
$